Suppose is real valued and is compact. Show that if the differential of does not vanish on then for all with support in and for all there is such that
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Spam yourself with math PhD qualifying-exam questions.
Let denote the set of Schwartz functions, and the dual space of tempered distributions. For let denote the distributional derivative of , and let be the distribution (i.e. , ). Let , equipped with the norm . Show that is a Hilbert space (with the norm being induced by the inner product), is dense in , and the inclusion map is compact.
Show that the set of Schwartz functions, , consisting of functions such that the seminorms , , are finite, is not a normed space, i.e. there exists no norm on giving rise to the locally convex topology induced by these seminorms. (Here is the set of non-negative integers.)
Recall that with the circle, the dual space of is the Banach space of finite Borel measures. Show that is closed in in the Banach topology induced by this duality, but is not closed in if the latter is equipped with the weak-* topology. Is closed in if is equipped with the weak topology?
Let denote the circle. Thus, can be identified with the space of -periodic functions on . Let denote the multiplication operator by : , and for (including ) let be the usual derivative.
Suppose that is a linear map (no continuity of any kind is assumed!) and satisfies and (on ). Show that there exists such that , i.e. for all .
(Hint: First show that if and then ; this shows that is multiplication by a function.)
Suppose that is any sequence of real numbers. Show that there exists a real valued function such that . (Hint: let identically 1 near 0, and choose appropriately so that and
converges in .)
Prove or disprove: If is an infinite dimensional separable Hilbert space, then is separable in the operator-norm topology.
Two quick problems.
(a) Suppose that is a function with the property that for all and for all there exists a polynomial on such that if . Is infinitely differentiable? Prove this or give a counterexample.
(b) Suppose that is a normed complex vector space with norm , and is linear but is not continuous. Show that is dense in .
Let be a -finite measure space. Let and let be the bounded linear operator on , .
(a) Find a necessary and sufficient condition (in terms of and ) for to have an eigenvector.
(b) Find a necessary and sufficient condition (in terms of and ) for to be compact.
Suppose is a compact operator on a Hilbert space . Prove that if is injective, and , then the image of is a closed subspace. Is this also true even if is not injective?